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5x^2-56x+151.25=0
a = 5; b = -56; c = +151.25;
Δ = b2-4ac
Δ = -562-4·5·151.25
Δ = 111
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-\sqrt{111}}{2*5}=\frac{56-\sqrt{111}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+\sqrt{111}}{2*5}=\frac{56+\sqrt{111}}{10} $
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